A) \[{{1}^{+}}\]
B) \[{{2}^{+}}\]
C) \[{{3}^{+}}\]
D) \[{{4}^{+}}\]
Correct Answer: C
Solution :
[c] According to Faraday's first law of electrolysis \[W=\frac{E\times i\times t}{96500}\] Where E = equivalent weight \[=\frac{mol.mass\,of\,metal(M)}{oxidation\text{ }state\text{ }of\text{ }metal\text{ }\left( x \right)}\] Substituting the value in the formula \[W=\frac{M}{x}\times \frac{i\times t}{96500}\] or \[x=\frac{M}{W}\times \frac{i\times t}{96500}=\frac{10\times 2\times 60\times 60}{96500\times 0.250}=3\] \[\left[ Given:no.\text{ }of\text{ }moles=\frac{M}{W}=0.250 \right]\] Hence oxidation state of metal is (+3)You need to login to perform this action.
You will be redirected in
3 sec