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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    Aluminium oxide may be electrolysed at \[1000{}^\circ C\] to furnish aluminium metal (At. Mass = 27 amu; 1 Faraday = 96,500 Coulombs). The cathode reaction is - \[A{{l}^{3+}}+3{{e}^{-}}\to Al\] To prepare 5.12 kg of aluminium metal by this method we require electricity of

    A) \[5.49\times {{10}^{1}}C\]     

    B) \[5.49\times {{10}^{4}}C\]

    C) \[1.83\times {{10}^{7}}C\]      

    D) \[5.49\times {{10}^{7}}C\]

    Correct Answer: D

    Solution :

    [d] 1 mole of \[{{e}^{-}}=1F=96500\text{ }C\] 27g of Al is deposited by \[3\times 96500C\] 5120 g of Al will be deposited by \[=\frac{3\times 96500\times 5120}{27}=5.49\times {{10}^{7}}C\]


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