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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    On passing current through two cells, connected in series containing solution of \[AgN{{O}_{3}}\] and \[CuS{{O}_{4}}\], 0.18 g of Ag is deposited. The amount of the Cu deposited is:

    A) 0.529 g

    B) 10.623 g

    C) 0.0529 g

    D) 1.2708 g

    Correct Answer: C

    Solution :

    [c] Using Faraday's second law of electrolysis, \[\frac{Weight\,of\,Cu\,deposoited}{Weight\,of\,Ag\,deposited}=\frac{Equ.\,wt.\,of\,Cu}{Equ.\,wt.\,of\,Ag}\] \[\Rightarrow \frac{{{w}_{Cu}}}{0.18}=\frac{63.5}{2}\times \frac{1}{108}\] \[\Rightarrow {{w}_{Cu}}=\frac{63.5\times 18}{2\times 108\times 100}=0.0529g.\]


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