A) \[-0.42\,\,V\]
B) \[-2.20\,\,V\]
C) 0.52 V
D) 1.04 V
Correct Answer: A
Solution :
[a] \[OC{{l}^{-}}\xrightarrow{{}}C{{l}^{-}};E{}^\circ =0.94V(I)\] \[C{{l}^{-}}\xrightarrow{{}}\frac{1}{2}C{{l}_{2}}+{{e}^{-}};E{}^\circ =1.36V(II)\] Add (I)+(II) \[OC{{I}^{-}}\xrightarrow{{}}\frac{1}{2}C{{l}_{2}};{{E}^{o}}=0.94-1.36\] \[=-0.42V\]You need to login to perform this action.
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