A) +0.09
B) +0.18
C) \[-0.09\]
D) \[-0.18\]
Correct Answer: D
Solution :
[d] \[2{{H}^{+}}+2{{e}^{-}}\xrightarrow{{}}{{H}_{2}}\] \[{{E}_{cell}}=0.06\,log[{{H}^{+}}]=0.06\times log\sqrt{{{K}_{a}}C}\] \[=0.06\times log{{10}^{-3}}=-0.18V\]You need to login to perform this action.
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