A) \[\frac{4}{3}\]
B) \[\frac{1}{3}\]
C) \[\frac{3}{3}\]
D) \[\frac{2}{3}\]
Correct Answer: C
Solution :
[c] Reduction half reaction: \[C{{r}_{2}}O_{7}^{2-}+6{{e}^{-}}~+14{{H}^{+}}\xrightarrow{{}}2C{{r}^{3+}}+7{{H}_{2}}O\] Oxidation half reaction: \[Cr\xrightarrow{{}}C{{r}^{3+}}+3{{e}^{-}}\] Overall reaction: \[C{{r}_{2}}O_{7}^{2-}+Cr~+14{{H}^{+}}+3{{e}^{-}}\xrightarrow{{}}3C{{r}^{3+}}+7{{H}_{2}}O\] 3F of electricity = 3 moles of \[C{{r}^{3+}}\] 1F of electricity \[=\frac{3}{3}\] moles of \[C{{r}^{3+}}\]You need to login to perform this action.
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