\[C{{u}^{+}}/Cu=+0.52V,\] |
\[F{{e}^{3+}}/F{{e}^{2+}}=+0.77V,\] |
\[\frac{1}{2}{{I}_{2}}(s)/{{I}^{-}}=+0.54V,\] |
\[A{{g}^{+}}/Ag=+0.88V\]. |
Based on the above potentials, strongest oxidizing agent will be: |
A) \[C{{u}^{+}}\]
B) \[F{{e}^{3+}}\]
C) \[A{{g}^{+}}\]
D) \[{{I}_{2}}\]
Correct Answer: C
Solution :
[c] Higher the value of reduction potential stronger will be the oxidising hence based on the given values \[A{{g}^{+}}\] will be strongest oxidizing agent.You need to login to perform this action.
You will be redirected in
3 sec