A) 1
B) 3
C) 5
D) 7
Correct Answer: B
Solution :
[b] The cell reaction is \[{{H}_{2}}(g)+{{I}_{2}}(s)\rightleftharpoons 2{{H}^{+}}(aq)+2{{I}^{-}}(aq)\] \[0.7714=0.535-\frac{0.0591}{2}\log \frac{{{[{{H}^{+}}]}^{2}}{{[{{I}^{-}}]}^{2}}}{{{P}_{{{H}_{2}}}}}\] pH=3You need to login to perform this action.
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