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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    On passing a current of 1.0 ampere for 16 min and 5 sec through one litre solution of\[CuC{{l}_{2}}\], all copper of the solution was deposited at cathode. The strength of \[CuC{{l}_{2}}\] solution was (Molar mass of Cu= 63.5; Faraday constant\[=96500Cmo{{l}^{-1}}\])

    A) 0.01 N              

    B) 0.01 M

    C) 0.02 M             

    D) 0.2 N

    Correct Answer: A

    Solution :

    [a] By Faraday's Ist law of electrolysis, \[\frac{W}{E}=\frac{Q}{96500}\] (where Q= it = charge of ion) We know that no. of gram equivalent \[=\frac{W}{E}=\frac{it}{96500}=\frac{1\times 965}{96500}=\frac{1}{100}\] (where i = 1 A,\[t=16\times 60+5=965\text{ }sec.\]) Since, we know that Normality \[=\frac{No.of\,gram\,equivalent}{Volume\text{ }\left( in\text{ }litre \right)}=\frac{\frac{1}{100}}{1}=0.01N\] 


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