A) \[P{{b}^{2+}}+SO_{4}^{2-}\xrightarrow{{}}PbS{{O}_{4}}\]
B) \[PbS{{O}_{4}}+2{{H}_{2}}O\xrightarrow{{}}Pb{{O}_{2}}+SO_{4}^{2-}\]\[+4{{H}^{+}}+2{{e}^{-}}\]
C) \[Pb\xrightarrow{{}}P{{b}^{2+}}+2{{e}^{-}}\]
D) \[P{{b}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Pb\]
Correct Answer: B
Solution :
[b] During charging, the lead storage battery behaves like an electrolytic cell. So, at anode the reaction is \[PbS{{O}_{4}}+2{{H}_{2}}O\xrightarrow{{}}Pb{{O}_{2}}+4{{H}^{+}}+SO_{4}^{2-}~+2{{e}^{-}}\]
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