A) \[N{{H}_{4}}\]
B) \[{{N}_{2}}\]
C) \[{{H}_{2}}\]
D) \[C{{l}_{2}}\]
Correct Answer: C
Solution :
[c] \[2N{{H}_{4}}Cl+Zn\to 2N{{H}_{3}}+ZnC{{l}_{2}}+{{H}_{2}}\uparrow .\]
You need to login to perform this action.
You will be redirected in
3 sec
