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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    The standard electrode potential \[\left( E{}^\circ  \right)\] for \[OC{{l}^{-}}/C{{l}^{-}}\] and \[C{{l}^{-}}/\frac{1}{2}C{{l}_{2}}\] respectively are 0.94 V and \[-1.36\text{ }V\]. The \[E{}^\circ \] value for \[OC{{l}^{-}}/\frac{1}{2}C{{l}_{2}}\] will be

    A) \[-0.42\,\,V\]

    B) \[-2.20\,\,V\]

    C) 0.52 V                           

    D) 1.04 V

    Correct Answer: A

    Solution :

    [a] \[OC{{l}^{-}}\xrightarrow{{}}C{{l}^{-}};E{}^\circ =0.94V(I)\] \[C{{l}^{-}}\xrightarrow{{}}\frac{1}{2}C{{l}_{2}}+{{e}^{-}};E{}^\circ =1.36V(II)\] Add (I)+(II) \[OC{{I}^{-}}\xrightarrow{{}}\frac{1}{2}C{{l}_{2}};{{E}^{o}}=0.94-1.36\] \[=-0.42V\]


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