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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    For a cell reaction involving two electron change, the standard EMF of the cell is 0.295 V at \[2{}^\circ C\]. The equilibrium constant of the reaction at \[25{}^\circ C\] will be:

    A) \[29.5\times {{10}^{-2}}\]       

    B) 10

    C) \[1\times {{10}^{10}}\]           

    D) \[2.95\times {{10}^{-10}}\]

    Correct Answer: C

    Solution :

    [c] Using the relation, \[E{{{}^\circ }_{cell}}=\frac{2.303RT}{nF}\log {{K}_{eq}}=\frac{0.0591}{n}\log {{K}_{eq}}\] \[\therefore 0.295V=\frac{0.0591}{2}\log {{K}_{eq}}\] Or \[\log {{K}_{eq}}=\frac{2\times 0.295}{0.0591}=10\] Or \[{{K}_{eq}}=1\times {{10}^{10}}\]


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