A) \[{{10}^{2}}\]
B) \[{{10}^{4}}\]
C) 10
D) \[{{10}^{3}}\]
Correct Answer: D
Solution :
[d] Molarity = 0.01 M ; Resistance = 40 ohm; Cell constant \[\frac{l}{A}=0.4\,c{{m}^{-1}}.\] Specific conductivity (k) \[=\frac{\text{cell constant}}{\text{resistance}}=\frac{0.4}{40}=0.01\text{ }oh{{m}^{-1}}\,c{{m}^{-1}}\] \[\text{Molar conductance}\left( {{\wedge }_{m}} \right)=\frac{1000\kappa }{Molarity}\]. \[=\frac{1000\times 0.01}{0.01}={{10}^{3}}oh{{m}^{-1}}\text{ }c{{m}^{2}}\text{ }mo{{l}^{-1}}\]You need to login to perform this action.
You will be redirected in
3 sec