A) 128
B) 125
C) 49
D) 50
Correct Answer: D
Solution :
[d] \[\Lambda _{m}^{\infty }(NaBr)=\Lambda _{m}^{\infty }(NaCl)+\Lambda _{m}^{\infty }KBr-\Lambda _{m}^{\infty }(KCl)\] \[\lambda _{m}^{\infty }(N{{a}^{+}})+\lambda _{m}^{\infty }(B{{r}^{-}})=126.5+151.5-150\] \[\lambda _{m}^{\infty }(N{{a}^{+}})=50\,Sc{{m}^{2}}e{{q}^{-1}}.\]You need to login to perform this action.
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