NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    Standard electrode potential for \[S{{n}^{4+}}/S{{n}^{2+}}\] couple is + 0.15 V and that for the \[C{{r}^{3+}}/Cr\] couple is\[-0.74V\]. These two couples in their standard state are connected to make a cell. The cell potential will be:

    A) +1.19 V           

    B) +0.89 V

    C) +0.18 V           

    D) +1.83 V

    Correct Answer: B

    Solution :

    [b] Given \[{{E}_{S{{n}^{4+}}/S{{n}^{2+}}}}=+0.15V\] \[{{E}_{C{{r}^{3+}}/Cr}}=-0.74V\] \[E_{cell}^{{}^\circ }=E_{cathode}^{{}^\circ }-E_{anode}^{{}^\circ }\] \[=0.15-\left( -0.74 \right)=+0.89V\]


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