2. Questions Bank
  3. NEET
  4. Chemistry
  5. Electrochemistry / विद्युत् रसायन

NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is \[100\Omega .\]. The conductivity of this solution is \[1.29\text{ }S\text{ }{{m}^{-1}}\]. Resistance of the same cell when filled with 0.02 M of the same solution is \[520\Omega \]. The molar conductivity of 0.02 M solution of electrolyte will be

    A) \[1.24\times {{10}^{-4}}\,S{{m}^{2}}mo{{l}^{-1}}\]

    B) \[12.4\times {{10}^{-4}}\,S{{m}^{2}}mo{{l}^{-1}}\]

    C) \[124\times {{10}^{-4}}\,S{{m}^{2}}mo{{l}^{-1}}\]

    D) \[1240\times {{10}^{-4}}\,S{{m}^{2}}mo{{l}^{-1}}\]

    Correct Answer: A

    Solution :

    [a] Conductivity \[(\kappa)=\frac{\ell }{R.a}\] \[\kappa =\frac{l}{R.a};\] cell constant. \[\left( \frac{l}{a} \right)~=1.29\times 100=129\] Again conductivity of 0.02M solution \[\kappa =\frac{1}{520}\times 129\] \[{{\Lambda }_{m}}=\frac{\kappa \times 1000}{M}=\frac{129}{520}\times \frac{1000}{0.02}\] \[=1.24\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner