| \[{{\Lambda }_{ClC{{H}_{2}}COONa}}=224\,oh{{m}^{-1}}c{{m}^{2}}g\,e{{q}^{-1}},\] |
| \[{{\Lambda }_{NaCl}}=38.2\,oh{{m}^{-1}}c{{m}^{2}}g\,e{{q}^{-1}},\] |
| \[{{\Lambda }_{HCl}}=203\,oh{{m}^{-1}}c{{m}^{2}}ge{{q}^{-1}},\] |
| What is the value of \[{{\Lambda }_{CIC{{H}_{2}}COOH}}\] |
A) \[288.5\,oh{{m}^{-1}}c{{m}^{2}}\,g\,e{{q}^{-1}}\]
B) \[289.5\,oh{{m}^{-1}}c{{m}^{2}}ge{{q}^{-1}}\]
C) \[388.8\,oh{{m}^{-1}}c{{m}^{2}}g\,e{{q}^{-1}}\]
D) \[59.5\,oh{{m}^{-1}}c{{m}^{2}}g\,e{{q}^{-1}}\]
Correct Answer: C
Solution :
[c] \[ClC{{H}_{2}}COONa+HCl\to ClC{{H}_{2}}OOH+NaCl\] \[{{\Lambda }_{ClC{{H}_{2}}COONa}}+{{\Lambda }_{HCl}}={{\Lambda }_{ClC{{H}_{2}}COOH}}+{{\Lambda }_{NaCl}}\] \[224+203={{\Lambda }_{ClC{{H}_{2}}COOH}}+38.2\] \[{{\Lambda }_{CIC{{H}_{2}}COOH}}=427-38.2\] \[=388.8\,oh{{m}^{-1}}c{{m}^{2}}g\,e{{q}^{-1}}\]
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