2. Questions Bank
  3. NEET
  4. Chemistry
  5. Electrochemistry / विद्युत् रसायन

NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    Electrode potentials \[\left( E{}^\circ  \right)\] are given below:
    \[C{{u}^{+}}/Cu=+0.52V,\]
    \[F{{e}^{3+}}/F{{e}^{2+}}=+0.77V,\]
    \[\frac{1}{2}{{I}_{2}}(s)/{{I}^{-}}=+0.54V,\]
    \[A{{g}^{+}}/Ag=+0.88V\].
    Based on the above potentials, strongest oxidizing agent will be:

    A) \[C{{u}^{+}}\]                       

    B) \[F{{e}^{3+}}\]

    C) \[A{{g}^{+}}\]                       

    D) \[{{I}_{2}}\]

    Correct Answer: C

    Solution :

    [c] Higher the value of reduction potential stronger will be the oxidising hence based on the given values \[A{{g}^{+}}\] will be strongest oxidizing agent.


You need to login to perform this action.
You will be redirected in 3 sec spinner