A) \[8.1\times {{10}^{4}}g\]
B) \[2.4\times {{10}^{5}}g\]
C) \[1.3\times {{10}^{4}}g\]
D) \[9.0\times {{10}^{3}}g\]
Correct Answer: A
Solution :
[a] \[\therefore Q=i\times t\] \[\therefore \text{ }Q=4.0\times {{10}^{4}}\times 6\times 60\times 60C=8.64\times {{10}^{8}}C\] Now since 96500 C liberates 9 g of Al \[8.64\times {{10}^{8}}\] C liberates \[\frac{9}{96500}\times 8.64\times {{10}^{8}}g\,Al=8.1\times {{10}^{4}}g\,of\,Al\]
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