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NEET Chemistry Electrochemistry / विद्युत् रसायन Question Bank Self Evaluation Test - Electrochemistry

  • question_answer
    \[{{I}_{2}}(s)|{{I}^{-}}(0.1M)\] half-cell is connected to a \[{{H}^{+}}\left( aq \right)\left| {{H}_{2}}\left( \text{1}bar \right) \right|Pt\] half cell and e.m.f. is found to be\[0.7714V.if\,{{E}^{{}^\circ }}_{{{I}_{2}}|{{I}^{-}}}=0.535\text{ }V\], find the pH of \[{{H}^{+}}|{{H}_{2}}\] half-cell.        

    A) 1                     

    B) 3     

    C) 5                                 

    D) 7

    Correct Answer: B

    Solution :

    [b] The cell reaction is \[{{H}_{2}}(g)+{{I}_{2}}(s)\rightleftharpoons 2{{H}^{+}}(aq)+2{{I}^{-}}(aq)\] \[0.7714=0.535-\frac{0.0591}{2}\log \frac{{{[{{H}^{+}}]}^{2}}{{[{{I}^{-}}]}^{2}}}{{{P}_{{{H}_{2}}}}}\] pH=3


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