A) Increases by \[30m\text{ }V\]
B) Decreases by \[30m\text{ }V\]
C) Increases by \[59m\text{ }V\]
D) Decreases by \[59m\text{ }V\]
Correct Answer: B
Solution :
[b] \[{{({{E}_{C{{u}^{2+}}/Cu}})}_{1}}={{E}^{0}}_{C{{u}^{2+}}/Cu}+\frac{0.059}{2}\log {{[C{{u}^{2+}}]}_{1}}\] \[[C{{u}^{2+}}(aq)+2{{e}^{-}}\xrightarrow{{}}Cu(s)\] and \[{{({{E}_{C{{u}^{2+}}/Cu}})}_{2}}={{E}^{0}}_{C{{u}^{2+}}/Cu}+\frac{0.059}{2}\log {{[C{{u}^{2+}}]}_{2}}\] \[\Rightarrow \Delta {{E}_{C{{u}^{2+}}/Cu}}=-\frac{0.059}{2}\log \left( \frac{{{C}_{2}}}{{{C}_{1}}} \right)\] \[=-\frac{0.059}{2}log\,10=-0.030V=-30\,mV\]
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