A) \[2a\alpha B\]
B) \[{{a}^{2}}\alpha B\]
C) \[2{{a}^{2}}\alpha B\]
D) \[a\alpha B\]
Correct Answer: A
Solution :
[a] At any time t, the side of the square a \[=({{a}_{0}}-\alpha t)\], where \[{{a}_{0}}=side\] at t=0. At this instant, flux through the square: \[\phi =BA\,\]\[\cos {{0}^{o}}=B{{({{a}_{0}}-\alpha t)}^{2}}\] \[\therefore \] emf induced \[E=-\frac{d\phi }{dt}\] \[\Rightarrow \,\,\,E=-B.2\,\,({{a}_{0}}-\alpha t)(0-\alpha )=+2\alpha aB\]
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