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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    Fig shown below represents an area \[A=0.5\,{{m}^{2}}\] situated in a uniform magnetic field \[B=2.0\,weber/{{m}^{2}}\] and making an angle of \[60{}^\circ \] with respect to magnetic field.               The value of the magnetic flux through the area would be equal to

    A) 2.0 weber          

    B) \[\sqrt{3}\text{ }weber~~~\]

    C) \[\sqrt{3}\text{/2 }weber\]          

    D) 0.5 weber

    Correct Answer: D

    Solution :

    [d] \[\phi =BA\,\cos \,\theta =2.0\times 0.5\times \cos \,{{60}^{o}}\] \[=\frac{2.0\times 0.5}{2}=0.5\,weber.\]


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