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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    The figure shows a conducting loop consisting of half circle of area \[A=0.06\,{{m}^{2}}\] and three straight segments. The half circle lies in a uniform changing magnetic field \[B=4{{r}^{2}}+2t+5\] (SI unit), where t is the time in second. An ideal battery E=2V is connected as shown and the total resistance of the wire is \[2\Omega \]. The net current in the loop is at t=5 second is:

    A) 1A 

    B) 1.5A           

    C) 0.26A

    D) 0.10A      

    Correct Answer: C

    Solution :

    [c] \[{{e}_{ind}}=\frac{d\phi }{dt}=\frac{d}{dt}(BA)=A\frac{dB}{dt}\]             \[=A\frac{d}{dt}(4{{t}^{2}}+2t+5)=A(8t+2)=0.06(8t+2)\] =2.52 at t=5 \[\frac{i=2-{{e}_{ind}}}{2}=0.26\,A\]


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