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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    A square loop with 2.0 m sides is perpendicular to a uniform magnetic field, with half the area of the loop in the field is shown in figure. The loop contains a 20.0 V battery with negligible internal resistance. If the magnitude of the field varies with time according to B = 0.042-0.871, with B in tesia and t in second. The net emf of the circuit is:

    A) \[20.0\,V\]

    B) \[18.26\,V\]

    C) \[21.74\,V\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] Induced emf. \[\left| \left. e \right| \right.=\frac{d\phi }{dt}=A\left( \frac{dB}{dt} \right)\] \[=\frac{2\times 2}{2}\times \frac{d}{dt}(0.042-0.87t)=2\times 0.87=1.74V\] The net induced emf\[=20+1.74=21.74\,V\]


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