A) \[\frac{9B\omega {{\ell }^{2}}}{2}\]
B) \[\frac{4B\omega {{\ell }^{2}}}{2}\]
C) \[\frac{5B\omega {{\ell }^{2}}}{2}\]
D) \[\frac{B\omega {{\ell }^{2}}}{2}\]
Correct Answer: C
Solution :
[c] For \[A:{{e}_{A}}=\frac{1}{2}B\omega {{(3\ell )}^{2}}\] and \[{{e}_{B}}=\frac{1}{2}B(-\omega ){{(2\ell )}^{2}}\] Resultant induced emf will be \[e={{e}_{A}}+{{e}_{B}}=\frac{1}{2}B\omega {{\ell }^{2}}(9-4)\] or \[e=\frac{5}{2}B\omega {{\ell }^{2}}\]
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