A) zero, \[\frac{Fr}{B\ell }\]
B) zero, zero
C) zero, \[\frac{Fr}{6B\ell }\]
D) \[\frac{Fr}{6B\ell },\,\frac{Fr}{6B\ell }\]
Correct Answer: C
Solution :
[c] There is no charge in flux through PS and so induced emf will be zero. But \[{{V}_{p}}-{{V}_{B}}={{V}_{Q}}-{{V}_{R}}\] Also, \[F=Bil\] or \[i=\frac{F}{B\ell }\] \[\therefore \,\,\,\,{{V}_{P}}-{{V}_{B}}={{V}_{Q}}-{{V}_{R}}=i{{r}_{QR}}=\frac{F}{B\ell }\times \frac{r}{6}=\frac{Fr}{6B\ell }\]
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