JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    A horizontal ring of radius \[r=\frac{1}{2}m\] is kept in a vertical constant magnetic field 1 T. The ring is collapsed from maximum area to zero area in 1 s. Then the emf induced in the ring is

    A) 1 V 

    B) \[(\pi /4)V\]

    C) \[(\pi /2)V\]

    D) \[\pi \,V\]

    Correct Answer: B

    Solution :

    [b] \[\left| \left. e \right| \right.=B\frac{dA}{dt}\]             \[\left| \left. e \right| \right.=B\frac{({{A}_{2}}-{{A}_{1}})}{({{t}_{2}}-{{t}_{1}})}\Rightarrow \left| \left. e \right| \right.=\frac{1\left( \frac{\pi }{4}-0 \right)}{(1-0)}\] \[e=\frac{\pi }{4}V\]


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