JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
                 A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across thering when its speed is v, is:  

    A) Zero           

    B) \[Bv\pi {{r}^{2}}/2\] and P is at higher potential   

    C) \[\pi rBv\] and R is at higher potential

    D) 2rBv and R is at higher potential

    Correct Answer: D


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