A) 1A
B) 1.5A
C) 0.26A
D) 0.10A
Correct Answer: C
Solution :
[c] \[{{e}_{ind}}=\frac{d\phi }{dt}=\frac{d}{dt}(BA)=A\frac{dB}{dt}\] \[=A\frac{d}{dt}(4{{t}^{2}}+2t+5)=A(8t+2)=0.06(8t+2)\] =2.52 at t=5 \[\frac{i=2-{{e}_{ind}}}{2}=0.26\,A\]You need to login to perform this action.
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