A) \[4\hat{i}-6\hat{j}\,m/s\]
B) \[-\,4\hat{i}+6\hat{j}\,m/s\]
C) \[3\hat{i}+2\hat{j}\,m/s\]
D) \[\sqrt{13}\hat{i}\,m/s\]
Correct Answer: C
Solution :
[c] For maximum potential difference the velocity must be perpendicular to the line AB, and so \[\vec{v}=v\,\sin \,\theta \hat{i}+v\,\cos \theta \hat{j}\] \[=v\left[ \frac{3}{\ell }\hat{i}+\frac{2}{\ell }\hat{j} \right]=\frac{v}{\ell }\left[ 3\hat{i}+2\hat{j} \right]\]You need to login to perform this action.
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