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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    A superconducting loop of radius R has self-inductance L. A uniform and constant magnetic field B is applied perpendicular to the plane of the loop. Initially current in this loop is zero. The loop is rotated by \[180{}^\circ \]. The current in the loop after rotation is equal to 

    A) zero

    B) \[\frac{B\pi {{R}^{2}}}{L}\]

    C) \[\frac{2B\pi {{R}^{2}}}{L}\]

    D) \[\frac{B\pi {{R}^{2}}}{2L}\]

    Correct Answer: C

    Solution :

    [c] Flux can't change in a superconducting loop.             \[\Delta \phi =2\pi {{R}^{2}}.B\] Initially current was zero, so self-flux was zero. \[\therefore \]  Finally \[Li=2\pi {{R}^{2}}\times B\] \[i=\frac{2\pi {{R}^{2}}\times B}{L}\]


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