A) 5 H
B) 6 H
C) 11 H
D) 12 H
Correct Answer: C
Solution :
[c] Initial current \[({{I}_{1}})=10\,A\]; Final current \[({{I}_{2}})=0\]; Time (t) = 0.5 sec and induced e.m.f. \[(\varepsilon )=220\] V. Induced e.m.f. \[(\varepsilon )\] \[=-L\frac{dI}{dt}=-L\frac{({{I}_{2}}-{{I}_{1}})}{t}=-L\frac{(0-10)}{0.5}=20L\] Or, \[L=\frac{220}{20}=11H\] [where L = Self inductance of coil]
You need to login to perform this action.
You will be redirected in
3 sec
