A) 0.48 H
B) 2.4 H
C) 0.12 H
D) 0.24 H
Correct Answer: D
Solution :
[d] \[M=\frac{{{\mu }_{0}}{{\mu }_{r}}{{N}_{1}}{{N}_{2}}}{2{{R}_{1}}}A\] \[=\frac{4\pi \times {{10}^{-4}}\times 800\times 500\times 25\times 12\times {{10}^{-4}}}{2\times 0.1}=0.24H\]
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