JEE Main & Advanced
Physics
Electro Magnetic Induction
Question Bank
Self Evaluation Test - Electromagnetic Induction
question_answer
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across thering when its speed is v, is:
A)Zero
B)\[Bv\pi {{r}^{2}}/2\] and P is at higher potential