A) 2.5 henry
B) 2.0 henry
C) 1.0 henry
D) 40 henry
Correct Answer: C
Solution :
[c] Total number of turns in the solenoid, N=500 Current, I =2A. Magnetic flux linked with each turn \[=4\times {{10}^{-3}}\,Wb\] As, \[\phi =LI\] or \[N\phi =LI\] \[\Rightarrow \,\,\,L=\frac{N\phi }{1}=\frac{500\times 4\times {{10}^{-3}}}{2}\] henry =1 HYou need to login to perform this action.
You will be redirected in
3 sec