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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    A generator has an e.m.f. of 440 Volt and internal resistance of 4000 hm. Its terminals are connected to a load of 4000 ohm. The voltage across the load is

    A) 220 volt

    B) 440 volt

    C) 200 volt

    D) 400 volt

    Correct Answer: D

    Solution :

    [d] Total resistance of the circuit = 4000 + 400 = 4400 W Current flowing \[i=\frac{V}{R}=\frac{440}{4400}=0.1\,amp\] Voltage across load = \[R\,i=4000\times 0.1=400\] volt.


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