A) \[9.1\times {{10}^{-11}}\,weber\]
B) \[6\times {{10}^{-11}}\,weber\]
C) \[3.3\times {{10}^{-11}}\,weber\]
D) \[6.6\times {{10}^{-9}}\,weber\]
Correct Answer: A
Solution :
[a] As we know, Magnetic flux, \[\phi =B.A\] \[\frac{{{\mu }_{0}}(2){{(20\times {{10}^{-2}})}^{2}}}{2[{{(0.2)}^{2}}+{{(0.15)}^{2}}]}\times \pi {{(0.3\times {{10}^{-2}})}^{2}}\] On solving \[=9.216\times {{10}^{-11}}=9.2\times {{10}^{-11}}\,weber\]
You need to login to perform this action.
You will be redirected in
3 sec
