JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Self Evaluation Test - Electromagnetic Induction

  • question_answer
    In a conducting cycle wheel (of n spokes), each spoke of length fi is rotating with angular speed \[\omega \] in uniform perpendicular magnetic field B. If due to flux cutting each metal spoke behaves as an identical cell of emf(e) then net emf of the system is             

    A) \[nB\omega {{l}^{2}}\]

    B) \[\frac{1}{2}nB\omega {{l}^{2}}\]

    C) \[\frac{1}{2}B\omega {{l}^{2}}\]

    D) \[B\omega {{l}^{2}}\]

    Correct Answer: C

    Solution :

    [c] each spoke will behave as a cell. Induced emf of each spoke \[=\frac{1}{2}B{{l}^{2}}\omega \] But all (n) identical spoke behaving as a cell can connected in a parallel fashion, so the resultant \[emf=e=\frac{1}{2}B{{l}^{2}}\omega \]= same as single cell.


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