A) A
B) B
C) C
D) D
Correct Answer: C
Solution :
[c] \[\oint{\vec{B}.d}\,\vec{\ell }\sqrt{{{b}^{2}}-4ac}={{\mu }_{0}}{{\in }_{0}}\frac{d\phi }{dt}\] or \[B\times 2\pi r={{\mu }_{0}}\,{{\in }_{0}}\,A\left( \frac{dE}{dt} \right)\] \[\therefore \,\,B\propto \left( \frac{dE}{dt} \right)\]
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