A) \[4\times {{10}^{-6}}T\]
B) \[6\times {{10}^{-8}}T\]
C) \[9\times {{10}^{-9}}T\]
D) \[11\times {{10}^{-11}}T\]
Correct Answer: B
Solution :
[b] \[c=\frac{E}{B}\Rightarrow B=\frac{E}{c}=\frac{18}{3\times {{10}^{8}}}=6\times {{10}^{-8}}T.\]
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