A) \[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\cos \,\omega t\]
B) \[-\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]
C) \[\frac{2{{E}_{o}}}{c}\hat{j}\,\sin \,kz\,\sin \,\omega t\]
D) \[\frac{2{{E}_{o}}}{c}\hat{j}\,\cos \,kz\,\cos \,\omega t\]
Correct Answer: C
Solution :
[c] Magnetic field vector, \[\vec{B}=\frac{2{{E}_{0}}}{c}\hat{j}\sin kz\sin \omega t\]You need to login to perform this action.
You will be redirected in
3 sec