JEE Main & Advanced Physics EM Waves Question Bank Self Evaluation Test - Electromagnetic Waves

  • question_answer
    The energy density of electromagnetic wave in vacuum is given by the relation

    A) \[\frac{{{E}^{2}}}{2{{\varepsilon }_{0}}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\]  

    B) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{1}{2}{{\mu }_{0}}{{B}^{2}}\]

    C) \[\frac{{{E}^{2}}+{{B}^{2}}}{c}\]

    D) \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}+\frac{{{B}^{2}}}{2{{\mu }_{0}}}\]

    Correct Answer: D


You need to login to perform this action.
You will be redirected in 3 sec spinner