A) \[{{V}_{A}}=\left( a+b+c \right)\frac{\sigma }{{{\varepsilon }_{0}}}\]
B) \[{{V}_{B}}=\left( \frac{{{a}^{2}}}{b}-b+c \right)\frac{\sigma }{{{\varepsilon }_{0}}}\]
C) \[{{V}_{C}}=\left( \frac{{{a}^{2}}+{{b}^{2}}}{b}+c \right)\frac{\sigma }{{{\varepsilon }_{0}}}\]
D) \[{{V}_{A}}={{V}_{B}}={{V}_{C}}=\left( a+b+c \right)\frac{\sigma }{{{\varepsilon }_{0}}}\]
Correct Answer: B
Solution :
[b] Potential due to a charged shell at an outside point \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{Q}{r}\] While that inside the shell\[=\frac{\sigma R}{{{\varepsilon }_{0}}}\], where R is the radius of the shell.You need to login to perform this action.
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