A) \[\frac{qa}{2d}\left( \frac{2d-a}{2d} \right)\]
B) \[\frac{qa}{2d}\left( \frac{2d-a}{d} \right)\]
C) \[-\frac{qa}{2d}\left( \frac{d-a}{d} \right)\]
D) \[-\frac{2qa}{d}\left( \frac{d-a}{2d} \right)\]
Correct Answer: C
Solution :
[c] \[\frac{k{{q}_{1}}}{a}+\frac{kq}{2d}=0\] \[\text{or }{{q}_{1}}=\frac{-\,qa}{2d}\] \[\frac{k{{q}_{1}}}{a}+\frac{kq}{2d}+\frac{k{{q}_{1}}}{d}=0\] \[\text{or }{{q}_{2}}=\frac{-qa}{2d}\left( \frac{d-a}{d} \right)\]You need to login to perform this action.
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