A) \[16\frac{{{n}_{2}}}{{{n}_{1}}}{{C}_{1}}\]
B) \[\frac{2{{C}_{1}}}{{{n}_{1}}{{n}_{2}}}\]
C) \[2\frac{{{n}_{1}}}{{{n}_{2}}}{{C}_{1}}\]
D) \[\frac{16{{C}_{1}}}{{{n}_{1}}{{n}_{2}}}\]
Correct Answer: D
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