A) \[\frac{3K{{\varepsilon }_{0}}A}{4d}\]
B) \[\frac{4K{{\varepsilon }_{0}}A}{4d}\]
C) \[\frac{\left( K+1 \right){{\varepsilon }_{0}}A}{2d}\]
D) \[\frac{K\left( K+3 \right){{\varepsilon }_{0}}A}{2\left( K+1 \right)d}\]
Correct Answer: D
Solution :
[d] \[{{c}_{1}}=\frac{\left( A/2 \right){{\varepsilon }_{0}}}{d/2}=\frac{A{{\varepsilon }_{0}}}{d},\] \[{{c}_{2}}=K\frac{A{{\varepsilon }_{0}}}{d},{{c}_{3}}=K\frac{A{{\varepsilon }_{0}}}{2d}\]You need to login to perform this action.
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