A) \[16\times {{(800R)}^{2}}\]
B) \[{{\left( \frac{800R}{4} \right)}^{-2}}\]
C) \[{{\left( \frac{1}{4\times 800R} \right)}^{2}}\]
D) None of these
Correct Answer: C
Solution :
[c] If, \[{{K}_{c}}=\frac{{{[{{N}_{2}}]}^{1/2}}{{[{{H}_{2}}]}^{3/2}}}{{{[N{{H}_{3}}]}^{1}}}=4\] Then, \[\frac{{{[N{{H}_{3}}]}^{2}}}{{{\left[ [{{N}_{2}}][{{H}_{2}}] \right]}^{3}}}={{(4)}^{-2}}=\frac{1}{16}\] also \[{{K}_{p}}={{K}_{c}}\cdot {{(RT)}^{\Delta {{n}_{g}}}}\] \[=\frac{1}{16}\times {{(800R)}^{-2}}={{\left( \frac{1}{4\times 800R} \right)}^{2}}\]
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