A) 1.0
B) 3.0
C) 0.5
D) 0.25
Correct Answer: A
Solution :
[a] \[\begin{align} & \begin{matrix} {} & {} & {} & HI\rightleftharpoons \frac{1}{2}{{H}_{2}}+\frac{1}{2}{{I}_{2}} \\ \end{matrix} \\ & \begin{matrix} at\,t=0 & 0 & {} & \begin{matrix} {} & 0 & {} & {} \\ \end{matrix} \\ \end{matrix} \\ & \begin{matrix} at\,eq. & (1-0.5) & (0.5) & (0.5) \\ \end{matrix} \\ \end{align}\] \[\left( \therefore \alpha =\frac{50}{100}=0.5 \right)\] Now \[{{K}_{C}}=\frac{{{(0.5)}^{1/2}}{{(0.5)}^{1/2}}}{0.5}=1\]
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